i had to bulid a small sircuit with one signal npn type tresistors and 2 resistors with @1kohms and another @ 10k ohms, we then had to test a transistor by doing a voltdrop test between the base and the emmiter. the resultwas 0.79v which ment that is was at the saturated point , i kew this result by looking at the region chart, when the result is over 1v it is in active region and when the result is more then it will not operate
step 2
then we did a voltdrop test between the colector and the emmiter, the result was 0.5v at the saturated point.its fully open thats why we only need 0.5v to pust it throgh.
at the VCE of 3v the power disspated by the transisots is 45w we figured this out by useing these calcultions p/w = A x V
15 x 3 = 0.45w
then we had to work out the beta of the transistor useing this formula
B = ic/ib
this is the kind of chart we use to find out what region the transistor is working in
the Vbe test doesn't tell you if a transistor is saturated, but whether it should be on. e.g .7 Vbe should be enough to turn the transistor on then your second test Vce tells you how much it is turned on. There are some calculations and explanations that are missing here.
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